EK #3, Lecture 1 Question

[Caffine]

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3. How many carbon atoms exist in 12 amu of C-12?

The answer in the back says "1" but shouldn't it be 6.02x10^23?

C-12 = 12 grams
1 amu = 1.66053886×10-24 grams

where the number of atoms "n" is equal to:
(amus in grams)n = grams
n = grams / (amu in grams)
n = avogadro's number

Whose right??? Even this so called teacher says their right but I disagree with him to: http://answers.yahoo.com/question/index?qid=20100113204926AAnYRua

 

[jphwki82]

Your teacher is correct. 1 mole of carbon would have 6.02 x 10 ^ 23 atoms of carbon. 1 atomic mass unit of carbon is the mass of 1 atom of carbon.
n in the equation below is moles. Moles = mass in grams divided by molar mass. You can then use the number of moles to calculate the number of molecules of a compound or atom via avagadro's number. 1 mole of any substance, Carbon Dioxide, water, ethylene, glucose, carbon, and etc, will have 6.02 x 10^23 molecules in the sample.

3. How many carbon atoms exist in 12 amu of C-12?

The answer in the back says "1" but shouldn't it be 6.02x10^23?

C-12 = 12 grams
1 amu = 1.66053886×10-24 grams

where the number of atoms "n" is equal to:
(amus in grams)n = grams
n = grams / (amu in grams)
n = avogadro's number

Whose right??? Even this so called teacher says their right but I disagree with him to: http://answers.yahoo.com/question/index?qid=20100113204926AAnYRua