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An object dropped from a height of 13 m strikes the ground at 16 m/s. In order for the object to strike the ground at 32 m/s, it must be dropped from:
A. 18m
B. 26m
C. 39m
D 52m
Answer is D according to EK.
V^2 = Vi^2 + 2ah
V^2 is proportional to height.
It makes sense mathematically, but doesn't this seem odd? Shouldn't it be dropped at 1.4h?
A. 18m
B. 26m
C. 39m
D 52m
Answer is D according to EK.
V^2 = Vi^2 + 2ah
V^2 is proportional to height.
It makes sense mathematically, but doesn't this seem odd? Shouldn't it be dropped at 1.4h?
