Electrochemistry ACS question

[suhshi]

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Why would

Increasing the concentration of Co2+ produce the most positive voltage for this half reaction

Co2+(aq) + 2e- >>>> Co(s) E=-0.28V


im not understanding the concept


thanks in advance

 

[sixkiller]

Why would

Increasing the concentration of Co2+ produce the most positive voltage for this half reaction

Co2+(aq) + 2e- >>>> Co(s) E=-0.28V


im not understanding the concept


thanks in advance

The given reduction potential is the EMF for the reaction.

E = E(std) + (0.06/n)log[Co++]

*the above version of the nerst equation has been re-arranged to omit negative signs so it might look different from what you're used to*

The given emf is at the STANDARD STATE (1 M)....

The Nerst equation tells us what happens to the emf as we deviate from the standard state.

According to the equation, emf will be most positive as Co++ increases

 

[marscole]

I dont think you have to know great details in real DAT. Just know whether 2 or more reactions couple and spont or non-spont....😉