endothermic

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which of the following must be true of a reaction that is nonspon at low temp and spont at higher temp?

Ans is Endothermic

can you explain why?

Use your equations here. Delta g = delta h - t*Delta S

If t is zero, delta g is delta h. Since it's nonspon, delta g is greater than zero, so delta h is greater than zero. Check with the converse. If t is very high, delta g is going to be very negative, regardless of what sign h has. Endothermic makes sense here. Hope that helps!
 
If T is very high, delta g is going to be very negative, how is that endothermic, It should be exothermic.

Shouldn't the answer be Endo or Exo depending on T
 
If T is very high, delta g is going to be very negative, how is that endothermic, It should be exothermic.

Shouldn't the answer be Endo or Exo depending on T

Endothermic or exothermic depends on enthalpy, spontanaeity depends on delta g. If t is high, delta g = delta h - very large number
Delta h = delta g + very large number
Delta h > 0 or endothermic

If t =0, delta g = delta h. If the reaction is spontaneous then delta g < 0, if it's not, delta g > 0. Since we're given it's not spontaneous at low temperatures delta g > 0, and delta h is also greater than zero. Which is endothermic.
 
Thanks, I can see it now , so we can we have a spont and endothermic at the same time, if delta H is negative then it is automatically spont and exothermic
If Delta H is positive then it can be spon or Non spon depending on how large T is.
 
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