Enols and temperature

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chiddler

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For a compound such as 2 butanone, adding a large base at lower temperature selects for the kinetic product with the unsub'd methyl being deprotonated.

Why does the lower temperature help select the kinetic product? Is it because higher temps allow rearrangement to occur?
 
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The reaction will still favor the thermodynamic product eventually, even when run at low temperatures, but it will take a long time. As in a ridiculously long time.

The kinetic product will have a small hill, and a mediocre final energy. The thermodynamic product will have a huge hill and a very favorable low final energy. The high temperature provides the oomph to get over this larger hill.
 
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