Enthalpy Change

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

paperaeroplane

Full Member
10+ Year Member
Joined
May 5, 2009
Messages
134
Reaction score
0
In this question from a TPRH passage, they give you two enthalpies of formation.

H(formation)1 = -297 kj/M
H(formation)2 = -297.1 kj/M

They then ask: What is the enthalpy change in the transformation of 1 to 2?

My process to answering was doing: H(formation)2 - H(formation)1. I thought you were supposed to do products - reactants to find the enthalphy change. And the answer I got was -.1 kj/mol.

However, the correct answer was .1 kj/mol and I don't understand why. Anyone understand? Thanks!
 
are you sure the question asks the formation from 1 to 2, not 2 to 1?
I also think it should be -.1 because 2 is more stable compound than 1 and transforming from 1 to 2 should release energy.
 
Top