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- Jun 23, 2011
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Given that @ 973K
MgCl2 + 1/2O2 <====> MgO + Cl2 Kp= 2.95atm^1/2
and
MgCl2 + H20 <=======> MgC +2HCl Kp= 8.40 atm
determine eq constant at 973for the eq:
2Cl2 + 2H20 <=======:> 4HCl + O2
I know they flipped the first eq and multiplied by 2 for both but mutliplying by 2 shouldnt change the Kp of either and flipping should make the Kp be the reciprocal (1/Kp). But how is the answer so large?
its 813atm
MgCl2 + 1/2O2 <====> MgO + Cl2 Kp= 2.95atm^1/2
and
MgCl2 + H20 <=======> MgC +2HCl Kp= 8.40 atm
determine eq constant at 973for the eq:
2Cl2 + 2H20 <=======:> 4HCl + O2
I know they flipped the first eq and multiplied by 2 for both but mutliplying by 2 shouldnt change the Kp of either and flipping should make the Kp be the reciprocal (1/Kp). But how is the answer so large?
its 813atm