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hey guys,
I need help on this gen chem question from Top Score..
Question:
In order to reach the equivalence point, what volume of a 5M NaOH solution is needed to titrate 0.25L of a 4M solution of HCL?
Answer:
0.2 L
Explanation:
5V = 0.25L (4)
V = 0.2 L
I don't get why the equation is the way it is...because it makes more sense (to me) to set up the equation as
5V = 4 (0.25 + V)
Because don't we have to consider the .25L that is already in the solution plus the remaining solution of NaOH we have yet to put in?
For the other titration questions (that don't include anything about equivalence points), I use this method and it works out well..
Any help is greatly appreciated.
Thank you!
I need help on this gen chem question from Top Score..
Question:
In order to reach the equivalence point, what volume of a 5M NaOH solution is needed to titrate 0.25L of a 4M solution of HCL?
Answer:
0.2 L
Explanation:
5V = 0.25L (4)
V = 0.2 L
I don't get why the equation is the way it is...because it makes more sense (to me) to set up the equation as
5V = 4 (0.25 + V)
Because don't we have to consider the .25L that is already in the solution plus the remaining solution of NaOH we have yet to put in?
For the other titration questions (that don't include anything about equivalence points), I use this method and it works out well..
Any help is greatly appreciated.
Thank you!