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When the ionized air molecules produce an average current of 2.5 ´ 104 A at the electrodes, how much power is being generated? (V = 5)
Obviously, the formula to use is P = IV.
(2.5 ´ 104 ) x (5) = 0.00125W = 1.25kw.
The answer says it is 1.25mW. This can't be true since there are 1,000,000 watts in 1 mW.
Right?????
Obviously, the formula to use is P = IV.
(2.5 ´ 104 ) x (5) = 0.00125W = 1.25kw.
The answer says it is 1.25mW. This can't be true since there are 1,000,000 watts in 1 mW.
Right?????