estimate Logs??
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I personally didn't come across one but here is what you do:
Say you need to estimate -log(5x10^-3)
By the log rule, that = -(log(5) + log(10^-3))
= -log(5) - (-3)log(10)
= -log(5) + 3log(10)
= 3 - log(5)
And since 0 < log(5) < 1 (as 5 is between 1 and 10), then your answer lies somewhere between 2 and 3. With that estimate you should be able to get your answer.
Say you need to estimate -log(5x10^-3)
By the log rule, that = -(log(5) + log(10^-3))
= -log(5) - (-3)log(10)
= -log(5) + 3log(10)
= 3 - log(5)
And since 0 < log(5) < 1 (as 5 is between 1 and 10), then your answer lies somewhere between 2 and 3. With that estimate you should be able to get your answer.
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YES! I would know how to do it. Without telling you anything about the actual test, I will say it would be in your best interest to know that. 😀
