Also, another thing you should understand is when you have two liquids mixed together, or when you add solute to a an otherwise pure liquid. Both of these instances result in a DECREASE in the vapor pressure.
In the first example, when you mix two liquids, the vapor pressure contributed to the total pressure above the liquid decreases for each component. That is, each liquid is contributing less to the total vapor pressure. The individual vapor pressure contributed by each liquid is equal to the mole fraction of that liquid x the partial pressure of that PURE liquid, Po. So, for example, if you mix liquid A with liquid B, the vapor pressure contributed by liquid a would be:
Va= Xa x Po
where Xa is the mole fraction of liquid a which is moles A/moles A + moles B
and Po is the partial pressure of Pure A. The same method can be used to find the vapor pressure contributed by liquid B, and when you add the two together you get the total pressure above the liquid contributed by each component of the mixture.
In case #2, the vapor pressure decreases due to the addition of a solute. The reason is because solute molecules take up space on the surface of the liquid, and so they decrease the surface area of the liquid. Thus, when you heat the liquid there are fewer liquid molecules entering the gaseous phase since some of the surface of the liquid is occupied by a salt particle, which has a very very high MP and will not enter the gaseous phase. This is why the VP is depressed upon the addition of solute