- Joined
- Jul 30, 2013
- Messages
- 26
- Reaction score
- 13
#22 A particle moves from position 1 to position 2 along a path C. It travels at a constant speed of 5pi m/s. At exactly half way through the trip its average vertical velocity is?
The answer is 10 m/s. I understand how to obtain the correct answer by dividing vertical displacement (5m) by time which is equal to distance / speed. In this case speed is given, but I don't know how they found the distance of 2pi5/4.
Similarly, #26 asks for the average acceleration of a particle moving from position 1 to position 2 along path C going a constant speed of 1 m/s.
The answer is 0.4/pi m/s^2. Acceleration = change in velocity / time. As with the last problem time is equal to distance / speed, and I am able to find all the variables besides distance. According to the answer key distance in this question is given as 2pi5/2.
How might I find the distance of 2pi5/4 in #22 and 2pi5/2 in #26?
Any help would be much appreciated! 🙂