Fast method for approaching PAT dice problems

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Hayang

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Hi guys, I took the DAT last year and wanted to show you guys something that helped me on the PAT.

It has to do with dice problems. Previously, I posted a thread on solving cubes in general here:
Cube Folding: Some Findings and Tips

It will help to read the above thread first.
Now, I'll show you a systematic way to approach DICE problems, where each side has 1~6 dots.

The Method
As soon as you realize that you're looking at a dice problem, you IMMEDIATELY look at the first choice and eliminate using the following steps:

Step 1 for elimination:
- Is there a 6? If yes, is it pointing the right way?
- Are there opposites?
Step 2:
- If there is a 2 or 3, check the VERTEX where all three sides meet.
- Do 2s and 3s point TOWARD or AWAY from the vertex? Do they point the wrong way?
Step 3:
- You have a possible correct answer. (The only question left: is the CHIRALITY correct?)
- See if you can eliminate other answers QUICKLY with Steps 1/2.
Step 4:
- If you have more than one correct candidate, then you must try to visualize whether you have a correct enantiomer: Remember you fold INTO the screen. If you put these two sides together, is the last one on the top or the bottom? The left or the right?

Example Problem 1
2cihac1.jpg

Okay, this is a dice problem. That means IMMEDIATELY you look at the first answer, and eliminate with the following method:

Choice A:
- Is there a 6: No
- Are there opposites: YES, 2 and 4 are opposites (Z-shape) therefore WRONG.

Choice B:
- Is there a 6: No
- Are there opposites: No
- Find the vertex where all three meet: The 3 and 2 share a side, so the 1 must touch on one of the two ends of that side. To the left of this side (between 3/2), there is a corner! This means that 3 and 5 touch, so that vertex is closed.
- The vertex where 2/3 and 1 touch is on the right, and 2 and 3 are POINTING TOWARD that vertex in the net.
- BUT in choice B the 3 and 2 point AWAY from the common vertex. So this is WRONG.

Choice C:
- Is there a 6: YES.
- Does the 6 POINT THE RIGHT WAY: NO. (WRONG!)

Choice D (Correct):
- Is there a 6: YES, and it points the right way (toward the 1)
- Are there opposites: NO
- Locate the vertex where all three meet. (Use the closest corner and walk out till you reach it) The two faces AWAY from the vertex where 6 and 1 meet. This is correct.

I'll post more examples when I have time, but I hope this helps! This step-by-step method made dice problems much more efficient for me, and its principles are useful for other cube problems too.
 
hey this is awesome thanks, just had some troubles with these parts
choice c:
- The vertex where 2/3 and 1 touch is on the right, and 2 and 3 are POINTING TOWARD that vertex in the net.
- BUT in choice B the 3 and 2 point AWAY from the common vertex. So this is WRONG.

and choice D

- Locate the vertex where all three meet. (Use the closest corner and walk out till you reach it) The two faces AWAY from the vertex where 6 and 1 meet. This is correct.

Having troubles with the vertex thing, thank you!
Hi guys, I took the DAT last year and wanted to show you guys something that helped me on the PAT.

It has to do with dice problems. Previously, I posted a thread on solving cubes in general here:
Cube Folding: Some Findings and Tips

It will help to read the above thread first.
Now, I'll show you a systematic way to approach DICE problems, where each side has 1~6 dots.

The Method
As soon as you realize that you're looking at a dice problem, you IMMEDIATELY look at the first choice and eliminate using the following steps:

Step 1 for elimination:
- Is there a 6? If yes, is it pointing the right way?
- Are there opposites?
Step 2:
- If there is a 2 or 3, check the VERTEX where all three sides meet.
- Do 2s and 3s point TOWARD or AWAY from the vertex? Do they point the wrong way?
Step 3:
- You have a possible correct answer. (The only question left: is the CHIRALITY correct?)
- See if you can eliminate other answers QUICKLY with Steps 1/2.
Step 4:
- If you have more than one correct candidate, then you must try to visualize whether you have a correct enantiomer: Remember you fold INTO the screen. If you put these two sides together, is the last one on the top or the bottom? The left or the right?

Example Problem 1
2cihac1.jpg

Okay, this is a dice problem. That means IMMEDIATELY you look at the first answer, and eliminate with the following method:

Choice A:
- Is there a 6: No
- Are there opposites: YES, 2 and 4 are opposites (Z-shape) therefore WRONG.

Choice B:
- Is there a 6: No
- Are there opposites: No
- Find the vertex where all three meet: The 3 and 2 share a side, so the 1 must touch on one of the two ends of that side. To the left of this side (between 3/2), there is a corner! This means that 3 and 5 touch, so that vertex is closed.
- The vertex where 2/3 and 1 touch is on the right, and 2 and 3 are POINTING TOWARD that vertex in the net.
- BUT in choice B the 3 and 2 point AWAY from the common vertex. So this is WRONG.

Choice C:
- Is there a 6: YES.
- Does the 6 POINT THE RIGHT WAY: NO. (WRONG!)

Choice D (Correct):
- Is there a 6: YES, and it points the right way (toward the 1)
- Are there opposites: NO
- Locate the vertex where all three meet. (Use the closest corner and walk out till you reach it) The two faces AWAY from the vertex where 6 and 1 meet. This is correct.

I'll post more examples when I have time, but I hope this helps! This step-by-step method made dice problems much more efficient for me, and its principles are useful for other cube problems too.
Hi guys, I took the DAT last year and wanted to show you guys something that helped me on the PAT.

It has to do with dice problems. Previously, I posted a thread on solving cubes in general here:
Cube Folding: Some Findings and Tips

It will help to read the above thread first.
Now, I'll show you a systematic way to approach DICE problems, where each side has 1~6 dots.

The Method
As soon as you realize that you're looking at a dice problem, you IMMEDIATELY look at the first choice and eliminate using the following steps:

Step 1 for elimination:
- Is there a 6? If yes, is it pointing the right way?
- Are there opposites?
Step 2:
- If there is a 2 or 3, check the VERTEX where all three sides meet.
- Do 2s and 3s point TOWARD or AWAY from the vertex? Do they point the wrong way?
Step 3:
- You have a possible correct answer. (The only question left: is the CHIRALITY correct?)
- See if you can eliminate other answers QUICKLY with Steps 1/2.
Step 4:
- If you have more than one correct candidate, then you must try to visualize whether you have a correct enantiomer: Remember you fold INTO the screen. If you put these two sides together, is the last one on the top or the bottom? The left or the right?

Example Problem 1
2cihac1.jpg

Okay, this is a dice problem. That means IMMEDIATELY you look at the first answer, and eliminate with the following method:

Choice A:
- Is there a 6: No
- Are there opposites: YES, 2 and 4 are opposites (Z-shape) therefore WRONG.

Choice B:
- Is there a 6: No
- Are there opposites: No
- Find the vertex where all three meet: The 3 and 2 share a side, so the 1 must touch on one of the two ends of that side. To the left of this side (between 3/2), there is a corner! This means that 3 and 5 touch, so that vertex is closed.
- The vertex where 2/3 and 1 touch is on the right, and 2 and 3 are POINTING TOWARD that vertex in the net.
- BUT in choice B the 3 and 2 point AWAY from the common vertex. So this is WRONG.

Choice C:
- Is there a 6: YES.
- Does the 6 POINT THE RIGHT WAY: NO. (WRONG!)

Choice D (Correct):
- Is there a 6: YES, and it points the right way (toward the 1)
- Are there opposites: NO
- Locate the vertex where all three meet. (Use the closest corner and walk out till you reach it) The two faces AWAY from the vertex where 6 and 1 meet. This is correct.

I'll post more examples when I have time, but I hope this helps! This step-by-step method made dice problems much more efficient for me, and its principles are useful for other cube problems too.
 
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