Choice D is more stable than choice A, but the question stem specifically states the compound is cis, while choice D is trans. I forget the technical explanation, but the way I do it is that every alternating carbon should be in the same position for cis. So for C-1 (isopropyl) is in the equatorial position, then cis side groups on C-3 and C-5 should be also equatorial and C-2,4,6 should be axial for them to be considered cis. methyl is on C-4 so the cis position is shown in A