Finding temp of equilibrium

[SaintJude]

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Edit: Nevermind!

If dH=44kJ & dS =118 J/K

At what temperature is the system at equilibrium. Answers: 373 K?

How did they get this number ??

dG= dH-TdS = 0 at equilibrium

 

[MedPR]

If dH=44kJ & dS =118 J/K

At what temperature is the system at equilibrium. Answers: 373 K?

How did they get this number ??

dG= dH-TdS = 0 at equilibrium

Oh wait, sorry I misread.

At equilibrium dG=0 by definition. Using G=-RTlnKeq, when Keq=1, G=0.

 

[SaintJude]

Lol--wait-nevermind even though I typed it right I thought it said "18" not 118---nevermind sorry!!

 

[pfaction]

...So I'll just chime in because it helps me;

dG = dH - TdS
0 (at equilib) = 44000-T(118)
44000=T(118)
44000/118 ~=~ 48000/120 is less than 400.