FL 1 Q 11 (Lenses)

[Neplina94]

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This seems so simple but for some reason I cant seem to get it. What am I not getting here? Please help! Thank you

A person, whose eyes has a lens-to-retina distance of 2.0 cm, can only see objects that are closer than 1.0 m away. What is the strength of the person’s eye lens? Use the thin-lens equation (1/O + 1/I = S)

A: -50 D

B: -10 D

C: 51 D

D: 55 D

 

[Flufpot12]

It’s 1/object distance (1) + 1/image distance (50), as stated in the question. Thus it adds up to 51

 

[Hi_I'mPaul]

This seems so simple but for some reason I cant seem to get it. What am I not getting here? Please help! Thank you

A person, whose eyes has a lens-to-retina distance of 2.0 cm, can only see objects that are closer than 1.0 m away. What is the strength of the person’s eye lens? Use the thin-lens equation (1/O + 1/I = S)

A: -50 D

B: -10 D

C: 51 D

D: 55 D

Check your units. lens-to-retina distance is 2 CENTI-meters. Object distance is 1 meter. Use equation given: 1/O+1/i=S, and covert all to meters then solve. So,
(1/2cm)+(1/1m)=S
50+1=S
S= 51 D

 

[Neplina94]

Check your units. lens-to-retina distance is 2 CENTI-meters. Object distance is 1 meter. Use equation given: 1/O+1/i=S, and covert all to meters then solve. So,
(1/2cm)+(1/1m)=S
50+1=S
S= 51 D

Thank you!

 

[Neplina94]

Check your units. lens-to-retina distance is 2 CENTI-meters. Object distance is 1 meter. Use equation given: 1/O+1/i=S, and covert all to meters then solve. So,
(1/2cm)+(1/1m)=S
50+1=S
S= 51 D

Thank you!