# Kaplan Exam FL 7 C/P Q17

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#### Pre-Med Oso

##### New Member
Hello there, I am trying to see how they converted to Angstrom. I know we have to use the following formula E = -Rh ( 1/n(initial)^2 - 1/n(final)^2 ( Rh = 2.18x10^-18). Does someone know the energy of a photon to Angstrom conversion it would help a lot thank you.

When an electron falls from n=3 to n=2 in a hydrogen atom, what is the value of the energy released, given that A is the energy needed to move an electron from the ground state of hydrogen atom to an infinite distance from the atom?

A: 0 A
B: 0.14A
C: 1.66A
D: 5.75A

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Hello there, I am trying to see how they converted to Angstrom. I know we have to use the following formula E = -Rh ( 1/n(initial)^2 - 1/n(final)^2 ( Rh = 2.18x10^-18). Does someone know the energy of a photon to Angstrom conversion it would help a lot thank you.

When an electron falls from n=3 to n=2 in a hydrogen atom, what is the value of the energy released, given that A is the energy needed to move an electron from the ground state of hydrogen atom to an infinite distance from the atom?

A: 0 A
B: 0.14A
C: 1.66A
D: 5.75A