Fluid Mechanics

[Teleologist]

Advertisement - Members don't see this ad

No clue how to approach this:

In a hydraulic lever consisting of two ideal fluid filled cylinder/pistons with a fluid filled line coupling the two cylinders, the output force is 100 times the input force. For 1 Joule of work done on the input side, the work done on the output side is (in J):

 

[DrknoSDN]

I believe it's 1 Joule input and output. Machines do not change the work done, only the force required to do the work.

So if 1 joule of imput requires moving the level 1 meter... 1 Joule of output would move the piston 1/100 of a meter and apply 100x the force. W = FD = (100) (1/100)

Hope i'm not completely wrong but that's my interpretation.

 

[Teleologist]

I think that's accurate, I googled simple machines and it does appear they never change the amount of work done but may change the force and the direction if the force (I.e. A pulley). Thank you for sharing that tidbit of information; I never understood that about machines until now! And indeed the answer is 1 joule.