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fraction exponents
- Thread starter Meredith92
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If you want to be precise, it's best to go through logs. http://forums.studentdoctor.net/showthread.php?t=980006 this is fairly detailed but a bit of overkill, if you ask me. Look at post (http://forums.studentdoctor.net/showpost.php?p=13617494&postcount=8) for a simpler and more reasonable way.
I doubt that we'll have to deal with anything but 1/2 and 1/3. As for 0.3 - that's pretty much 1/3 and 10^0.3 should be about 2.1 or so.
I doubt that we'll have to deal with anything but 1/2 and 1/3. As for 0.3 - that's pretty much 1/3 and 10^0.3 should be about 2.1 or so.
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Using the premise behind this trick in the case of positive exponents, you can estimate this pretty closely. Given this trend:
10^3 = 1 x 10^3
10^3.5 = ~3 x 10^3
10^4 = 1 x 10^4
10^4.5 = ~3 x 10^4
Since the decimal 3 in 10^.3 is less than 5, we know the mantissa will be less than three, with an exponent of 10^0.
We can therefore estimate 10^.3 to be <3 x 10^0 so some value less than 3. That should be close enough.
10^3 = 1 x 10^3
10^3.5 = ~3 x 10^3
10^4 = 1 x 10^4
10^4.5 = ~3 x 10^4
Since the decimal 3 in 10^.3 is less than 5, we know the mantissa will be less than three, with an exponent of 10^0.
We can therefore estimate 10^.3 to be <3 x 10^0 so some value less than 3. That should be close enough.
