free electrical charge particle and UCM

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SaintJude

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An isolated electrically charged particle travels at speed v inside a uniform magnetic field of strength B.

Why will this particle undergo centripetal motion?
 
And did you guys know this was the basis of the Rutherford model? Is this true? If so, it's a good passage topic question...Rutherford + magnetic fields..

Saw this on wiki answers

Rutherford's model of atom stated that all the positive charge was concentrated in the center together and electrons revolved around it but the classical theory of physics states that "If a charged particle undergoes circular motion, then it is subjected to accelerate and an accelerating particle would loose energy".
Thus, the electrons revolving around the nucleus would go in a spiral path and ultimately
fall into the nucleus as there path will continue to shrink and the atom will collapse. But this does not happen.

So, Rutherford's model of atom was discarded.
 
The force from the magnetic field on the particle is always perpendicular to its direction. That makes the acceleration of the particle to be always perpendicular to its direction and a motion where you have an acceleration with constant magnitude always perpendicular to the velocity is a uniform circular motion.
 
An isolated electrically charged particle travels at speed v inside a uniform magnetic field of strength B.

Why will this particle undergo centripetal motion?

What milski said is right, but if you're confused still try watching this lecture on wikipremed. There is a problem exactly like this and it is explained pretty thoroughly.

http://www.wikipremed.com/course_videos.php?syl=02&video_code=010403_01

If you don't want to watch the whole thing, fastforward to about halfway through. The question pops up right around the 22 minute mark.
 
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