Freezing point depression

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Question about freezing point...

Find the freezing point of a solution with 23g ethanol dissolved in 250g water with Kf = 1.86.

freezing point = (m)(Kf)(i) :::: where i, is the number of particles dissociated (something like that from destroyer).... here would i = 2???

does ethanol in water dissociate? because according to the answer, i=1...

Thanks in advance.

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Im not 100% sure, but i think the reason ethanol doesnt dissociate is because the hydrocarbons.
 
For ethanol and other nonelectrolytes, i is 1. It would be 2 for NaCl.
 
i thought the freezing point equation was just:

freezing point=(Kf)(m)...where does 'i' come from?!
 
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Yeah, I’m confused now too. If the solute were to dissociate, wouldn’t it just be reflected in the molality since the moles of solute would be doubled?
 
Well, that is true, but it is easier just to multiply the molality by 2 than make two calculations for the molalities of each ion in solution.

For example, if you had MgCl2, which would dissociate into three ions. Suppose you had 3 moles of it on 1 kg solvent. This would be the calculation- deltaT= (3)[3/1](1.86), much easier than just adding all of the molalities together.

Correct me if I am wrong please.
 
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