For anyone with EK1001 Physics, do you care to explain #312 solution to me? I am pretty much 😕 after reading the solution to the problem. To begin with, I know that force up is tension and force down is weight. But why is frictional force downwards as well? The solution has T = mg + f => T = 2mg which I'm not sure why. Thanks
Friction and Torque problem
- Thread starter shffl
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Without having the book in front of me, I would say that since tension can be equation with the force applied, the friction would be in the opposite direction.
I wish SDN had a smart board feature. But basically, Tension is pulling up and resisting the downward motion of weight right?
So knowing this, you've got T = mg + Force of friction.
AND....
Force of Friction is equal to the normal force right which is weight, times the coefficient right? That explains why it's 2mg.
I wish SDN had a smart board feature. But basically, Tension is pulling up and resisting the downward motion of weight right?
So knowing this, you've got T = mg + Force of friction.
AND....
Force of Friction is equal to the normal force right which is weight, times the coefficient right? That explains why it's 2mg.
