Hmm I may be just dumb or just filled with so much of info that my mind has gone somewhere but help me on this plz..
In order to find pH of a solution.. do we always change it to Kb (of Ka given) and then later subtract pOH from 14?
Ex) If we titrated 100ml of HClO with 0.1M NaOH (40mL)... I found that the conc. of HClO was 0.04M in order to reach eq. point... and Ka given at 3.00x10^-8
But when since we know the conc. HClO.. can't we just do x^2 = (3.00x10^-8)(0.040M)
and then just negative log it? lol
In order to find pH of a solution.. do we always change it to Kb (of Ka given) and then later subtract pOH from 14?
Ex) If we titrated 100ml of HClO with 0.1M NaOH (40mL)... I found that the conc. of HClO was 0.04M in order to reach eq. point... and Ka given at 3.00x10^-8
But when since we know the conc. HClO.. can't we just do x^2 = (3.00x10^-8)(0.040M)
and then just negative log it? lol