gauge p vs. hydrostatic pressure vs. atm--a problem that combines them all

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SaintJude

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A large cylinder is filled w/ an equal volume of two immiscible fluids. A balloon is submerged in the first fluid; the gauge pressure , Pg1, in the balloon at the deepest point in the first fluid is found to be 3 atm. Next, the balloon is lowered all the way to the bottom of the cylinder; and as it is submerged in the second fluid, the hydrostatic pressure , Pg2, in the balloon reads 8 atm. What is the ratio of the gauge pressure at the bottom of the first fluid to the gauge pressure at the bottom of the second fluid? (Atmospheric pressure = 1 atm).

Does anyone have a drawing for this? I'll try to look for one as well...
 
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3/7? Unless they reset the gauge for fluid 2, then it would be 3/4. Am I wrong?
 
Yeah, it's 3:4. Yo milski, could please change those values accordingly so I can re-draw & post correct label.

Currently, from top to bottom the atmosphere on the diagram is:
3, 1,4, 3, 8
How should I change those numbers...

Is anyone else still CONFUSED...oi.
 
Gauge pressure is just normal pressure with the zero set at a convinient place, normally Patm. The idea is that you want to measure only the pressure of the fluid, not any additional pressure. If they want to reset gauge pressure at the 1/2 surface, you need to change a bit:
At the surface: Patm=1, P0=1, Pg=0, Phs=1
At the interface: Patm=1, P0=1, Pg=3, Phs=4
Now we reset the gauge.
At the interface: Patm=1, P0=4, Pg=0, Phs=4
At the bottom: Patm=1, P0=4, Pg=4, Phs=8

Whatever you do, P0+Pg=Phs
 
Yes, the graphs are correct. The blue is ok as absolute pressure or if you want to use the same terminology as the rest of the problem, it's hydrostatic pressure.
 
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