N2 + 3H2 <--> 2NH3
8 moles of N2, 8 moles of H2 are placed in a 2 liter flask and allowed to come to equilibrium. @ equilibrium, 2 moles of NH3 are formed. Calculate the Keq.
I'm not following the solution. It does an ICE chart, which I get, but not the calculation that follows afterwards.
Can someone explain why the ICE for 2NH3 (product) is
I: 0
C: +2x
Equilibrium: 2/2 = 1M
Therefore, 2x =1 , x = 0.5
How can they conclude with the above statement?
8 moles of N2, 8 moles of H2 are placed in a 2 liter flask and allowed to come to equilibrium. @ equilibrium, 2 moles of NH3 are formed. Calculate the Keq.
I'm not following the solution. It does an ICE chart, which I get, but not the calculation that follows afterwards.
Can someone explain why the ICE for 2NH3 (product) is
I: 0
C: +2x
Equilibrium: 2/2 = 1M
Therefore, 2x =1 , x = 0.5
How can they conclude with the above statement?