I need help in understanding what happens if Lead Iodide has a Ksp of 7 times 10 the power -9 at 25 C. What statement is true if some potassium iodide is added to a saturated solution of PbI2. It says that the solubility product remains the same but the molar solubility decreases......why? Because is it the fact that u are adding Iodine to make the reaction shift to the left and once you are shifting to the left you want to decrease PbI2? What about the other way around?
GC Destroyer Question problem #228 on page 200(2019 Destroyer)
- Thread starter nsudental
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Here it is....This is simply the common ion effect......The Iodide shifts the equilibrium to the LEFT,,,,,this will make more of the solid.....hence its solubility will DECREASE.....The Ksp stays the same , since it is only changed by temperature, and not any common ion. If this does not help, kindly consult a standard General Chem text such as Chang or Zumdahl.
Hope this helps
Dr. Jim Romano
Hope this helps
Dr. Jim Romano
