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Can someone explain this question (on qvault) to me:
The solubility of dissolved oxygen in water is 1.25 x 10-4 M at 25°C, where the atmospheric mole fraction of oxygen is 0.21 and atmospheric pressure is 1.0 atm. In a pure oxygen atmosphere at the same pressure, what would the solubility be?
(correct answer: (1.25×10−4)/0.21 M)
Intuitively, I thought that in pure oxygen atmosphere, more oxygen gas will enter the solution (water) and so the solubility would increase, but the solubility in the answer is smaller than the original solubility which is 1.25 x 10-4 M.
Edit: wow, I feel dumb
The solubility of dissolved oxygen in water is 1.25 x 10-4 M at 25°C, where the atmospheric mole fraction of oxygen is 0.21 and atmospheric pressure is 1.0 atm. In a pure oxygen atmosphere at the same pressure, what would the solubility be?
(correct answer: (1.25×10−4)/0.21 M)
Intuitively, I thought that in pure oxygen atmosphere, more oxygen gas will enter the solution (water) and so the solubility would increase, but the solubility in the answer is smaller than the original solubility which is 1.25 x 10-4 M.
Edit: wow, I feel dumb
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