GC question
Started by dmasterpeezy
My guess is that they only gave you the Ka for the first proton. You don't know the Ka for the second proton.
Also, this is a weak acid so you can't assume full deprotonation.
Bro easy weak acid equation. It's square root of (HAKA)!!
That would give you the H+ concentration and then take the negative log of that. Works every time. No ice tables bro!!!!!
That would give you the H+ concentration and then take the negative log of that. Works every time. No ice tables bro!!!!!
No I'm not mad bro. Just got MAD excited lol. I love that trick of square root of HAKA
What study material is this question from?
So, dmasterpeezy do you understand the explanation?
yeah makes sense kinda.. but its weird that here we dont, but if we were doing an M1V1 question then we would use 2 protons
M1V1 should only be used for dilution problems, and N1V1= N2V2 is for neutralization reactions. And if you forgot what N was, it is the molarity times the coefficient.
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On the real dat as my friends told me there are no weak acid equations where you need to take into account the first Ka and then the second Ka. If it's a weak diprotic acid, only take the first proton into account. For weak acid problems remember you won't have to do a ice table. Remember that the trick to do weak acid problems is the square root of (HA x Ka) = [H+]. Try my way at home kids and if it doesn't work then I'll buy you a red porsche 911 with a Swedish blond sitting in the passenger side!
