GC question

[299678]

Advertisement - Members don't see this ad

What mass of KClO3 will produce 48.0 g of oxygen gas O2, if the decomposition of KClO3 is complete? (molar mass of KClO3 = 122.5 g / mol)

Answer is 122.5 g I need your explanation. Thank you

 

[299678]

Never mind ! I found out a solution from previous post.

2KClO3 --> 2KCl + 3O2

Find Moles of O2 produced:
48g of O2 * 1mol/32grams O2 = 1.5 moles of 02

Mole Ratio to get moles of KClO3 needed to produce 1.5 moles of O2
1.5 moles of 02 * 2 mol KCLO3/3 mol O2 = 1 mol of KClO3 produced from 48 grams of O2

Convert Moles to grams:
1 mol of KClO3 = 122.5 grams KClO3