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[yakuza]

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So I was trying to help these girls on a gchem problem and couldn't figure it out...


A hydrocarbon was burned in a bomb calorimeter. The temperature of the calorimeter and the 1.00 kg of water rose from 20.45'C to 23.65 'C. The heat capacity of the calorimeter, excluding water, is 2.21 kJ/'C. What is the heat released by combustion?

answer: 20.5 kJ

 

[Seenary]

I thought I worked it out but I guess not...the answer may be incorrect.

delta H = mc delta T
= (1000g)(2.21KJ/C)(3.21)
= 7094.1 KJ

Input would be appreciated

 

[yakuza]

I thought I worked it out but I guess not...the answer may be incorrect.

delta H = mc delta T
= (1000g)(2.21KJ/C)(3.21)
= 7094.1 KJ

Input would be appreciated

I found out, nvm but thx guys.

You add 7094 + qcalorimeter which is found by

q=C x dT

C being heat capacity

 

[Phloem01]

For bomb questions isn't it Qrxn = -(Qwater + Qbomb) so don't you need to know the specific heat of water to do this...??