gen chem destroyer question 192

[Strikeout13GB]

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i get the whole ICE chart but I dont know where they are getting the 2x=1 part from, he doesnt show any of the work for that part

 

[rnbaxter]

i get the whole ICE chart but I dont know where they are getting the 2x=1 part from, he doesnt show any of the work for that part

Can you just post the question, not everyone has destroyer to reference your question and figure it out in order to help you.

 

[Strikeout13GB]

yea sorry, consider the following: N2 + 3H2 <--> 2NH3, if 8 moles of N2 and 8 moles of H2 are placed in a 2 liter flask and allowed to come to quilibrium. At equilibrium, 2 moles of NH3 are formed. Calculate the Keq.

 

[rjm546]

i get the whole ICE chart but I dont know where they are getting the 2x=1 part from, he doesnt show any of the work for that part

In the question it states that at Equilibrium you have 2 moles of NH3. Also, earlier in the ques it stated that it was placed in a 2 L flask.

SO, Divide 2moles/2L= 1M of NH3. Now you have that known concentration and the change was 2X.

All you have to do now is find X from 2X= 1M of NH3