okay so Freezing point depression is acquired using
delta = (Kf)(m) while the m is known to be molaLity which is moles of solute/kg of solvent right?
thing is, in chad's video. he simply converted 1 m of BaCl2 to 3 for the molal value that he used in his example
i know that BaCl2 dissociates into 3 particles, but how is it assumed that the value is 3 even though nothing is said about the solvent in g/L/kg? or can i just assume that 1 m of BaCl2 was 1 mole/1 liter which would be 1 kg anyways? BUT if i DO assume that, that 1 liter is of the SOLUTION and not the solvent, so I am a bit confused here...
if anyone watched chad's vids and know what im talking about, please enlighten me
EDIT: nevermind, he started with 1 MOLAL of BaCl2, not Molarity, haha
delta = (Kf)(m) while the m is known to be molaLity which is moles of solute/kg of solvent right?
thing is, in chad's video. he simply converted 1 m of BaCl2 to 3 for the molal value that he used in his example
i know that BaCl2 dissociates into 3 particles, but how is it assumed that the value is 3 even though nothing is said about the solvent in g/L/kg? or can i just assume that 1 m of BaCl2 was 1 mole/1 liter which would be 1 kg anyways? BUT if i DO assume that, that 1 liter is of the SOLUTION and not the solvent, so I am a bit confused here...
if anyone watched chad's vids and know what im talking about, please enlighten me
EDIT: nevermind, he started with 1 MOLAL of BaCl2, not Molarity, haha
