292. Find the element possessing the set of quantum numbers [5, l, -l, +l/2] for its last electron. 1) 31Ga 2) 47Ag 3) 50Sn 4) 81Tl 5) none of these ANS: 5 How is this problem correct? Ok primary quan number is 5 so 2^2=50 which make sense to be 3 right? since SN has 50 protons. and also 1 is the L then it means it has S and P orbitals that SN does have and -1 would mean Px. How is it None of the above?

Five answer choices? You might want to reconsider the materials. While it's a good question, five answer choices is not realistic, so the materials may not be realistic. n = 5 thus fifth shell l = 1 thus p-orbital ml = -1 so it's a px orbital ms = +1/2, so it's spin up This means that we need to look at the first element in the fifth row of the p-block to find the element with those quantum numbers for the last electron. That happens to be In, element 49.

thanks but had the problem been [5, l, -l, + and - l/2] it would of been SN right? since -1 mean Px which is either In or Sn but since there are two electrons now then it'll be SN right? I know its not realistic I just found this online, I needed to brush up on my Gen Chem.