Gen Chem Question

[Pinbear]

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It is a rate law question.

RxN is 2 C2H6 + 7 O2 --> 4 CO2 + 6 H2o

it is first order to C2H6 and first order to 7 O2

Then how do you express rate law?

Rate: k(C2H6)(O2) ????

or

Rate: k*1/2(C2H6)1/7(O2)

I like to know how coeffiecient works in the rate law.

Thanks

 

[SuperCool101]

I haven't studied for the DAT in a while (and im taking it in August!!)

but i belive that you do not factor in the coefficents.

it should be like this:
Rate Law = k [C2H6] x [O2]

The first order means that the concentration of both O2 and C2H6 will be to the power of 1.

If O2 was to the second order, then it would be like this:
Rate Law = k [C2H6] x [O2]^2

Hope im right

 

[UndergradGuy7]

Rate: k(C2H6)(O2)

 

[CANgnome]

can't it be (O2)^2 or (C2H6)^2 as well for second order

 

[UndergradGuy7]

can't it be (O2)^2 or (C2H6)^2 as well for second order

Yes, if its 2nd overall but he said it is first order to C2H6 and first order to O2.

He didn't say 2 overall.