Gen Chem question

[thejamespark]

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This may come as a dumb question but...

What is the net ionic equation for the reaction between aqueous silver nitrate and aqueous potassium chloride?
a)K+(aq) + NO3-(aq) → KNO3(s)
b)AgNO3(aq) + KCl(aq) → AgCl(s) + KNO3(aq)
c)Ag+(aq) + Cl-(aq) → AgCl(s)
d)Ag+(aq) + Cl-(aq) + K+(aq) + NO3-(aq) → AgCl(s) + K+(aq) + NO3-(aq)

Answer: C
Can someone elaborate how I can look at these type of questions? K+, NO3- are spectator ions but still not sure where to start on these kinds of questions :/

 

[thejamespark]

ah nm. i figured it out. 😀
part of solubility rules.

 

[srizzo25]

When working with these types of problems it's best to follow these 3 steps:
1. Write the molecular equation (the overall balanced chemical reaction)
2. Write the total ionic equation
3. Write the Net ionic equation

* Once you practice a few of these types of problems it becomes easy to visualize the net ionic equation without having to write out each step.

Your question asks what is the net ionic equation for the reaction between aqueous silver nitrate and aqueous potassium chloride?

1. AgNO3 (aq) + KCL (aq) ---> AgCl (s) + KNO3 (aq)

* In writting out the molecular equation you need to understand the type of chemical reaction occuring and which products will form from the reaction. This is a double displacement reaction. you also need to understand the solubility rules which tell you whether or not the product formed will be soluble or insoluble. In this case AgCl will be insoluble and form as a precipitate.

2. Ag+ (aq) + NO3- (aq) + K+ (aq) + Cl- (aq) --> AgCl (s) + K+ (aq) + NO3- (aq)

* In this step you break apart the soluble compounds into there ions. Again you need to know the solubility rules to be able to do this.

3. Ag+ (aq) + Cl- (aq) --> AgCl (s)

* The last step is just simplfying the equation by canceling out what appears on both sides. The net ionic equations tells us what is happening in the chemical reaction. In this reaction, Ag+ and Cl- react to form a precipitate AgCl.

* K+ and NO3- are spectator ions and are left out of the net ionic equation.

Hope this Helps.

 

[DrRoyal Pains]

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