General Chemistry Question (STOICHIOMETRY)

[kkhan]

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What is the percent yield for a reaction in which 1.40 grams of SB2S3 is obtained from 1.73 grams of antimony and a slight excess of sulfur?

Sb2S3 molar mass: 339.7 grams

A) 80.9%
B) 58.0%
C) 40.5%
D) 29.0 %

..cannot figure out how to calculate this' any general chemistry guru would be appriciated, thanks

 

[joonkimdds]

sulfur is excess so we know anitomy is limiting reagent.
write the balanced equation and i think it's
2Sb + 3S = 1SB2S3
for 2 mol of Sb, 1 Sb2S3 exist.
you got 1.73 g of anitomy which is 0.014 mol.
so you should have 0.007 mol of Sb2S3.
but you ended up having 1.4g of Sb2S3 which is 0.004mol.
percent yield is actual/theoratical x 100
0.004/0.007 x100 = 4/7 x 100 = 0.57 x 100 = 57 %.

I wish to be a gen chem guru 🙂

 

[kkhan]

thankss, and some kudoss'