Glucose has 4 Chiral Centers ; but when I look at the ring form it seems like 5?

[MedicalMan14]

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C1, C2, C3, C4 & C5 all seem chiral to me. What am I doing wrong?

 

[BerkReviewTeach]

C1, C2, C3, C4 & C5 all seem chiral to me. What am I doing wrong?

You are correct. In the straight chain form, it has four stereogenic carbons (2, 3, 4, and 5). But when it forms a ring, the carbonyl can be attacked from top or bottom, forming a new chiral center at C1. Hence, the alpha and beta anomers are formed.