good dat q's

[queenskillers]

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is trans always 1,2 and 1,4 on the ring with either both equatorial (major) or both axial?

in Zn(s)lZn 2+ ll Cu 2+ lCu(s), why is Zn the one that is chosen to be on the left side (anode) that makes it get oxidized. Zn is more electronegative than copper and thus it should be the one getting reduced and accepting electrons so shouldnt it be on the right side of cell (reduced).

in the destroyer, to extract benzoic acid (a weak acid?), it says we need to used NaHCO3 (weak base?). I thought that you use weak bases to extract strong acids and strong bases to extract weak acids.

 

[queenskillers]

are these that hard? come on someone has to know them you guys are all gunners

 

[jigabodo]

are these that hard? come on someone has to know them you guys are all gunners

It's cuz most people on this forum are already done with DAT at this point...so they can care less.

 

[Mstoothlady2012]

is trans always 1,2 and 1,4 on the ring with either both equatorial (major) or both axial?

yes

 

[D.D.S.]

in Zn(s)lZn 2+ ll Cu 2+ lCu(s), why is Zn the one that is chosen to be on the left side (anode) that makes it get oxidized. Zn is more electronegative than copper and thus it should be the one getting reduced and accepting electrons so shouldnt it be on the right side of cell (reduced).
QUOTE]

Oxidation of other crap happens at the anode, therefore Zn gets reduced. Reduction of other stuff occurs at the cathode, so cathode gets oxidized. Its weird.. but think of the the solution the zinc and copper are in. so the solution that zinc is in will get oxidized, therefore its on the left (An Ox). The solution that copper is in, will get reduced, (Red Cat).


Hope this helps.. sorry im tired and its 4:42 am, and im done with DATs but still here to help cuz people helped me here as well.... good luck...

 

[moralbrain]

is trans always 1,2 and 1,4 on the ring with either both equatorial (major) or both axial?

in Zn(s)lZn 2+ ll Cu 2+ lCu(s), why is Zn the one that is chosen to be on the left side (anode) that makes it get oxidized. Zn is more electronegative than copper and thus it should be the one getting reduced and accepting electrons so shouldnt it be on the right side of cell (reduced).

in the destroyer, to extract benzoic acid (a weak acid?), it says we need to used NaHCO3 (weak base?). I thought that you use weak bases to extract strong acids and strong bases to extract weak acids.

On the ring, if the carbons with the substituents are odd number away from each other, they will be on the same side (either equatorial or axial). In contrast, if the carbons with the substituents are even number away from each other, they will be on the diff side (one on axial while one on equatoria l)

When we do electrochemistry, the major concern should be the reduction potential. The more negative the reducing potential, the stronger the reducing agent. The more positive the reducing potential, the stronger the oxidizing agent. Reduction potential for Zn is
-0.76, while Cu has 0.34 (you can find this value from reduction potential table). Zn has more negative value, so it would be oxidized (reducing agent)

For the last one, yeah you are right. But sometimes you can actually use weak base to extract weak acid also. Lets say you have a mixture of weak acid and strong acid, and you want to extract both differently. In this case, you are going to have to use weak base first to extract strong acid first. Because if you use strong base, both weak and strong acid will react with the base and you wont be able to distinguish them. However, if you use weak base, only the strong acid will react with it and you are going to be able to extract the weak acid later. I think Destroyer just wanted to make the point of base usage for acid extraction.