-
CycleTrack and SDN are teaming up to make medical school admissions more transparent and accessible! Read the announcement to learn how we’re supporting the future of CycleTrack’s free application-tracking tools .
H NMR Help
Started by Psa
Get help with your application
Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.
There are only 2 groups: the H's on the aromatic and the hydrogens on the carbon attached the oxygen.
It's considered a singlet because they are all equivalent to each other and are part of the same group. Equivalent hydrogens don't alter the singlet/doublet thingie.
It's considered a singlet because they are all equivalent to each other and are part of the same group. Equivalent hydrogens don't alter the singlet/doublet thingie.
I get that there are 2 groups due the symmetry of the molecule. But I still dont get why the the neighboring H's in the ring don't count.
I'm pretty sure it's because equivalent hydrogens don't affect the multiplicity of the peak. Don't wanna give you the wrong answer though.
According to my notes on Chads: neighbors = nonequivalent hydrogens less than 3 bonds away.
According to my notes on Chads: neighbors = nonequivalent hydrogens less than 3 bonds away.
Last edited:
I think i get it. You're saying that the whole benzene ring is considered a single group, just like the 3 H's in the methyl are considered one. I'm just confused because I thought that whenever the H's were on separate carbons, they always got the n+1 amount of peaks as the neighboring H's.
for the benzene ring keep in mind that those double bonds are not fixed i.e. there is a delocalization of electrons and therefore you only see 1 H. i think thats why
I definitely remember chad mentioning that now! I need to re-watch some stuff b4 my test
yup im rewatching certain sections as well for GC and OC! when is your test?
oh good luck! how long have you been studying?
