H NMR of cyclohexane

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Good question...not sure, but let me take a stab.
There are 2 H's on each carbon and they're essentially "equivalent" due to the rapid ring-flipping that happens at room temp, so if one H is axial at any one moment it can be equatorial the next. And due to cyclohexane's symmetry you see every C is the same. So essentially every H is the same and since NMR doesn't read symmetrical protons, you end up with a strong singlet, perhaps?
 

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