H NMR of cyclohexane
Started by 30somethingyearold
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Good question...not sure, but let me take a stab.
There are 2 H's on each carbon and they're essentially "equivalent" due to the rapid ring-flipping that happens at room temp, so if one H is axial at any one moment it can be equatorial the next. And due to cyclohexane's symmetry you see every C is the same. So essentially every H is the same and since NMR doesn't read symmetrical protons, you end up with a strong singlet, perhaps?
There are 2 H's on each carbon and they're essentially "equivalent" due to the rapid ring-flipping that happens at room temp, so if one H is axial at any one moment it can be equatorial the next. And due to cyclohexane's symmetry you see every C is the same. So essentially every H is the same and since NMR doesn't read symmetrical protons, you end up with a strong singlet, perhaps?
Why do you think it would be a triplet?
Great, thanks @suchbrio that does make sense! I got so confused, I thought it was a doublet then a triplet (no logical reasoning behind it!)....neither right!
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