Hardy Weinberg Equilibrium

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

futuredoctor10

Full Member
15+ Year Member
Joined
Jan 25, 2007
Messages
1,625
Reaction score
21
So when given a Hardy Weinberg equilibrium problem, if you are told 14 out of 100 members of a population EXHIBIT or EXPRESS a recessive trait:

then q^2 = 0.14
and you can find q, p, 2pq, whatever the question asks for.

How else could a problem be worded (for example, how would they word a problem to indicate "q" instead of expressed q^2?)
 
So when given a Hardy Weinberg equilibrium problem, if you are told 14 out of 100 members of a population EXHIBIT or EXPRESS a recessive trait:

then q^2 = 0.14
and you can find q, p, 2pq, whatever the question asks for.

How else could a problem be worded (for example, how would they word a problem to indicate "q" instead of expressed q^2?)

they could say the 14 are "homozygous for the the recessive allele"
 
So when given a Hardy Weinberg equilibrium problem, if you are told 14 out of 100 members of a population EXHIBIT or EXPRESS a recessive trait:

then q^2 = 0.14
and you can find q, p, 2pq, whatever the question asks for.

How else could a problem be worded (for example, how would they word a problem to indicate "q" instead of expressed q^2?)

They would say the frequency of the allele in the gene pool is q. From this value, you usually can deduce the number of homozygotes for q (q^2), homozygotes for p (p^2) and heterozygotes (2pq).
 
Top