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Here is the question followed by the solution. Im not getting it and I know its easy. Help please. A population of fish is in Hardy-Weinberg equilibrium. Red-colored scales are a dominant trait and blue-colored scales are a recessive trait. In the population, 36% of the fish display red-colored scales. What percent of the population in the next generation is expected to be homozygous dominant?
The Hardy-Weinberg equation is p + q = 1, and p2 + 2pq + q2 = 1, where:
p2 = homozygous dominant
2pq = heterozygous
q2 = homozygous recessive
The general strategy for all Hardy-Weinberg problems is that we have to find the individual values of p and q, and then use those values to solve for what the question is asking. We’re given that 36% of the population shows a dominant phenotype, and this number includes both homozygous dominant and heterozygous dominant phenotypes. If 36% show the dominant phenotype, then 64% of the population shows the recessive phenotype. In accordance to the above equations:
q2 = 0.64
q = 0.80
p = 0.20
p2 = (0.20)2 = 0.04 X 100 = 4%
The Hardy-Weinberg equation is p + q = 1, and p2 + 2pq + q2 = 1, where:
p2 = homozygous dominant
2pq = heterozygous
q2 = homozygous recessive
The general strategy for all Hardy-Weinberg problems is that we have to find the individual values of p and q, and then use those values to solve for what the question is asking. We’re given that 36% of the population shows a dominant phenotype, and this number includes both homozygous dominant and heterozygous dominant phenotypes. If 36% show the dominant phenotype, then 64% of the population shows the recessive phenotype. In accordance to the above equations:
q2 = 0.64
q = 0.80
p = 0.20
p2 = (0.20)2 = 0.04 X 100 = 4%