HBr + alkene

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

hausee

Full Member
10+ Year Member
15+ Year Member
Joined
Nov 20, 2006
Messages
595
Reaction score
0
if no other condition given, which will be the favoriable reaction intermediates for reaction R-CH=CH-R + HBr?

1. carbon cation
2. radicals

This is from ADA full test. I think it can go either way, right? if no condition given? (means with light and regular atmosphere)

Thanks😴
 
Last edited:
Pretty sure it will always say HV or light if they want you to recognize that it is going to go through a radical intermediate rather than a carbocation intermediate. Regardless, the product should be the same.
 
Pretty sure it will always say HV or light if they want you to recognize that it is going to go through a radical intermediate rather than a carbocation intermediate. Regardless, the product should be the same.

products aren't the same. if the mechanism is carried out through a radical intermediate, the br will attach first, and then the H will attach to the more substituted carbon, leading to anti markovnikov. if it is through a carbocation, the h will attach first, and then the Br will attach to the more substituted carbon, IE markovnikov. the radical mechanism will not lead to a change in sterochemistry, while the carbon cation mechanism will lead to a mixture.

if a question like that does come up, i would pick the carbocation method just because the other one would require an input of energy, IE light and wouldnt be favored in the overall picture. if u just threw hcl and an alkene together, u get a reaction through a carbocation intermediate. you would have to add light if you want a radical intermediate.
 
yea i somehow missed the fact that you said radical vs carbocation intermediates on the previous post

a question tho: how do I know when HBR + alkene will go with the radical or the carbocation intermediate route? do i assume radical when i see heat/light and carbocation if i see nothing?
 
I guess if there is no reaction condition given, it will go through carbon cation; If light/peroxide is included, it go through radicals.
 
Top