Help me solve this rotational motion problem

Started by bonoz
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bonoz

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Problem: "How long does it take for a 33-rpm record to rotate once, at constant speed? A) 0.033 seconds B) 0.29 s C) 2.66 s D) 3.33 s.

I first coveted 33 rpm into rps. I divided 33 rpm by 60 seconds and got 0.55 rps.

After this I can only think of dividing 0.55 by 1 to get the time it takes to complete 1 revolution. I get 1.81 seconds.

What am I doing wrong? is there a blatant equation I should be using?
 
that is weird lol
i get what you get

33 times in 60 seconds.
so 1 time would take 60/33 = 1.81 seconds.

work backwards:
1.81 seconds per turn. 33 turns = 1 minute.

WTF
 
If you get flustered with these types of questions, an alternate solution can be to focus on the units.


33 rotations per minute
...is the same as...
33 rot/min (rot = rotations, min = minutes) (1)

Convert to seconds

33 rot/min * 1 min / 60 sec
=33/60 rot/sec (2)

You want the amount of time it takes to rotate once
...which is the same as...
sec/rot (seconds per rotation)

to obtain that, take the inverse of (2)

(33/60 rot/sec)^-1
=60/33 sec/rot
A quick glance gives you a value that is a bit less than 2 (66/33 being 2).

EDIT: Looks like you were right all along.
 
Last edited:
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you are all wrong

you forgot to factor in the DJ that was using this record to scratch thereby slowing the rotations by 0.8 seconds.. therefore the correct answer is C at 2.6 seconds
 
you are all wrong

you forgot to factor in the DJ that was using this record to scratch thereby slowing the rotations by 0.8 seconds.. therefore the correct answer is C at 2.6 seconds

If you get flustered with these types of questions, an alternate solution can be to focus on the units.


33 rotations per minute
...is the same as...
33 rot/min (rot = rotations, min = minutes) (1)

Convert to seconds

33 rot/min * 1 min / 60 sec
=33/60 rot/sec (2)

You want the amount of time it takes to rotate once
...which is the same as...
sec/rot (seconds per rotation)

to obtain that, take the inverse of (2)

(33/60 rot/sec)^-1
=60/33 sec/rot
A quick glance gives you a value that is a bit less than 2 (66/33 being 2).

EDIT: Looks like you were right all along.

Nicely explained.