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[Mamona]

Find f[g(x)] if f(x) = x^2 – 2x + 3 and g(x) = x + 1.

The answer is x^2 + 2

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[harrygt]

Find f[g(x)] if f(x) = x^2 – 2x + 3 and g(x) = x + 1.

The answer is x^2 + 2

Because you are looking for f [g(x)], all you have to do is plug g(x) in each x in the f(x) relation. It will be (x+1)^2 - 2(x+1) + 3 = x^2 + 2

 

[artanis]

Hey, the question is asking for F of G of x. So sub g(x) = x + 1 into the equation f (x) = x^2 - 2x + 3. So wherever you see an x, sub in x = (x + 1)

(f(g(x)) = (x+1)^2 - 2(x+1) + 3 = x^2 + 2x + 1 -2(x+1) + 3 = x^2 + 2x + 1 - 2x - 2 + 3 = x^2 + 2

Find f[g(x)] if f(x) = x^2 – 2x + 3 and g(x) = x + 1.

The answer is x^2 + 2

 

[Ilkaan]

Find f[g(x)] if f(x) = x^2 – 2x + 3 and g(x) = x + 1.

The answer is x^2 + 2

(x +1)^2 -2(x+1) + 3
(x^2 + 2x + 1) -2x-2 + 3
x^2 + 2x + 1-2x-2 + 3 do the cancelation and addition
you will get
x^2 + 2
Hope that will help

 

[Mamona]

Thank you very much guys I got it now!!!!