Help with a problem part 2

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

djtiesto14

The One & Only, DJ Tiesto!
15+ Year Member
Joined
May 4, 2007
Messages
339
Reaction score
56
Points
4,621
  1. Dental Student
Advertisement - Members don't see this ad
Can someone explain this problem to me?
 

Attachments

  • Moles.jpg
    Moles.jpg
    42.9 KB · Views: 117
you're probably just forgetting to divide by liters to get molarity. Any K equilibrium constant is defined as the [products]/[reactants], thus ((0.4*14.25)/3) is your molarity of each product, 40% of 14.25 moles divided by the volume in liters to get molarity, and your concentration of reactant is (14.25*.6)/3, thus gives ((1.9)^2)/2.85=k I just wrote it as squared but it really means that each of your products concentration is 1.9M because they decomposed from the same reactant.
 
Top Bottom