help with calc Q

[waterloowannabe]

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hey

This q is:

Given the equation (y^2)-2x+3 = 0, find dy/dx
What I did was solve for y and then differentiate to get
y' = 1/((2x-3)^(1/2))

the actual answer was 1/y and they used implicit differentiation to get it..
but why is my answer wrong?
Or is there a way to get 1/y using my method?

Thanks!

 

[waterloowannabe]

ok, I figured it out
( I would have deleted the thread, but I dont know how to do it )

when you solve for y, you get y = (2x-3)^(0.5)

just sub that into the anwer I got for the derivative, and you get 1/y

thanks

 

[JonPrePharmD]

ok, I figured it out
( I would have deleted the thread, but I dont know how to do it )

when you solve for y, you get y = (2x-3)^(0.5)

just sub that into the anwer I got for the derivative, and you get 1/y

thanks

This should help you do it the right way
[YOUTUBE]5yTVUZCaU6k[/YOUTUBE]

More examples here: http://patrickjmt.com/derivatives-more-implicit-differentiation-examples/