Help with dat problem please

[rinsterman12]

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I can't get this problem right

A painting which is 4 feet wide and 5 feet
long is surrounded by a rectangular frame
6-inches wide. What percent of the area of
the picture and the frame is occupied by
the frame?

The answer is 30 1/2 i believe​

 

[UndergradGuy7]

I don't know if this is right but...

If the area of the painting is 4*5 = 20. The frame is 6 inches wider on each side (or 0.5 feet) so 4+(0.5) and 5+(0.5) are the length and width of the frame. We can do (4+0.5) * (5+0.5) = 24.75 which is the area of the frame, but the frame has an empty area in the middle... it is a frame. So we need to subtract the 24.75 of the frame - 20 from the picture to give us the area of the frame, so 24.75-20 = 4.75.

So area of frame/total area * 100 is the percent
4.75/(24.75) = 19%

 

[UCB05]

I can't get this problem right

A painting which is 4 feet wide and 5 feet
long is surrounded by a rectangular frame
6-inches wide. What percent of the area of
the picture and the frame is occupied by
the frame?

The answer is 30 1/2 i believe​

the painting is 4'x5' = 20sqft, with 6 inches, or .5' of frame on each side.
Total area, then, is (4+0.5+0.5)' x (5+0.5+0.5) = 5'x6' = 30sqft

the area of the frame is 30-20=10sqft

% of area occupied by the frame is 10/30 x100 = 33.3%