Help with Keq

[20445593]

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This is a stupid question, but I cannot find the answer. Specifically, CH4 + CL2 <-> CH3CL + HCL

Keq = [CH3CL]^1 [HCL]^1 / [CH4]^1 [CL]^1

The Keq equals 1.1 x 10^19... However, the book doesn't give me the values by which they arrived at the answer... can someone help me? I get how many grams per mol, how to calculate molarity, but I still cannot get my calculator to reflect the same answer..

 

[Cptn Loko]

You have not provided sufficient information to figure out this problem. At the very least you would need the molarity of one reactant and one product at equilibrium.

 

[SN2ed]

Thread closed. These types of questions belong in the Study Q&A forum.